WAEC 2019 Physics Practical Answer


ANSWER:

(1a)

Tabulate
L(cm) |130.0|110.0|90.0|70.0|50.0|
t^1(s) |.47.5|43.1|39.6|35.0|29.0|
t^2(s) |47.1|43.5|39.4|34.6|29.2|
t=t^1+t^2/2(s) |47.3|43.3|39.5|39.8|29.1|
T(s) |2.365|2.165|1.975|1.740|1.455|
T^2(s^1) |5.593|4.687|3.901|3.028|2.117|
L=30(cm) |100.0|80.0|50.0|40.0|20.0|
(1ix)
Graph.(will be updated)
(1x)
Slop (will be updated)
(1xi)
(i) K1=4x^2/s intercept C =1.32
=4/0.043*22/7*22/7=978.842
(ii) K2=C/S= 1.32 / 0.043=30.698
(1xii)
(i) I avoid parallax error in the metre rule and stop
(ii) I avoid conical oscillation
(1bi)
The period of oscillation of a body is time taken by body to complete one oscillation.
(1bii)
If a body is falling under its own weight alone the rate of change of its velocity with time as a result of earth gravitational pull is known as the acceleration of free fall due to gravity
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(3a)

Tabulate
S/N: 1,2,3,4,5,6
S(ohms) : 15,12,10,8,6,4
V(v): 0.45,0.52,0.57,0.75,0.86,1.10
1/v(v^-1) : 2.20,1.92,1.75,1.30,1.16,0.90
(3vii)
Graph (will be updated)
(3viii)
Slop (will be updated)
(3ix)
Will be updated
(3x)
(i) I avoided parallax error when taking readings from the voltmeter
(ii) I ensured that the key was opened when reading is not been taking
(3bi)
Resistivity is a measure of the resistance of a given size of material to electrical conduction. It is measured in ohms – meter (πm)
(3bii)
Given that
E=1.5v, R=1π, r=2π
I =E/R+r=1.5/1+2
= 1.5/3= 0.5A
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